(x-5)^2/4-(y-2)^2/9=4

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Solution for (x-5)^2/4-(y-2)^2/9=4 equation: 


x in (-oo:+oo)

t_1 = -(((y-2)^2)/9)-4

((x-5)^2)/4+t_1 = 0

((x-5)^2)/4+(4*t_1)/4 = 0

(x-5)^2+4*t_1 = 0

4*t_1+x^2-10*x+25 = 0

(4*t_1+x^2-10*x+25)/4 = 0

(4*t_1+x^2-10*x+25)/4 = 0 // * 4

4*t_1+x^2-10*x+25 = 0

4*t_1+x^2-10*x+25 = 0

DELTA = (-10)^2-(1*4*(4*t_1+25))

DELTA = 100-4*(4*t_1+25)

100-4*(4*t_1+25) = 0

100-4*(4*t_1+25) = 0

-16*t_1 = 0

-16*t_1 = 0

-16*t_1 = 0 // : -16

t_1 = 0

DELTA = 0  <=>  t_4 = 0

x = 10/(1*2) i t_1 = 0

x = 5 i t_1 = 0

( x = ((100-4*(4*t_1+25))^(1/2)+10)/(1*2) or x = (10-(100-4*(4*t_1+25))^(1/2))/(1*2) ) i t_1 > 0

( x = ((100-4*(4*t_1+25))^(1/2)+10)/2 or x = (10-(100-4*(4*t_1+25))^(1/2))/2 ) i t_1 > 0

t_1+0 > 0

t_1 > 0

t_1+0 > 0 // - 0

t_1 > 0

x in { 5, ((100-4*(4*(-(((y-2)^2)/9)-4)+25))^(1/2)+10)/2, (10-(100-4*(4*(-(((y-2)^2)/9)-4)+25))^(1/2))/2 }

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